Question

The weights of A and B are in ratio 5 is to 7 if be alone weighs 28 kg the weight of a is

Answer 1

Answer:

20 kgs

Step-by-step explanation:

Given:

a:b = 5:7

b = 28kg

To find:

Weight of a

Proof:

$\frac{a}{b} = \frac{5}{7}$

On substituting b value on the above expression, we have,

$\frac{a}{28} = \frac{5}{7}$

$a = \frac{5 \times 28}{7}$

$a = 5 \times 4$

$a = 20kg$

Therefore, the weight of a is 20kgs.

Hope it helps you.

Good Luck.

Answer 2

Step-by-step explanation:

Let theAof Divya =x

Then the ratio of the weight of Divya and Himanshu will be x:28 kg

According to the given statement

x:28::5:7

By cross product rule

Product of extremes = Product of means

x×7=(28×5) kg

x=20 kg

Weight of Divya =20 kg