Question

The well 12 m deep with a diameter 3.5 m is dug up and earth from it is evenly spread to form a platform 10.5 m long an 8.8 m wide. Find the height of the platform.

Answer 1

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HerE IS YouR AnsweR ————

now, depth or height of well = 12 m ------ (h)


diameter of well = 3.5 m

therefore , radius = 3.5 ÷ 2 = 1.75 m ------ ( r )


let the height of platform be h.

Length of rectangular platform = 10.5 m ------ ( l )

& breadth of platform = 8.8 m ------- (b)


[ here, we opt for volume because in this
condition the one thing is transformed into another thing.]

therefore,


$volume \: of \: cylindrical \: well \: = volume \\ of \: rectangular \: platform \\ \\ = > \pi {r}^{2}h = l \times b \times h \\ \\ = > \frac{22}{7} \times 1.75 \times 1.75 \times 12 = 10.5 \times 8.8 \times h \\ \\ = > \frac{22 \times 1.75 \times 1.75 \times 12}{10.5 \times 8.8} = h \\ \\ = > 1.25 = h$

therefore, height of platform is 1.25 m.



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Answer 2

Step-by-step explanation:

see this what I solved

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