Question

the well 7 m in radius and 22.5 has to be dug. the soil thus obtained is spread over a rectangular field of sides 21 m × 15 m to make a platform. how high will be the platform

Answer 1

Volume of well =πr²h
=22/7×49×22.5
=3465m³

Volume of rectangle=l×b×h
=21×15×h
=315cm²h


3465=315h
3465/315=h
11m=h

Answer 2

The height of platform will be 11 m

Step-by-step explanation:

Radius of dug = 7 m

Height of dug = 22.5 m

Volume of dug = $\pi r^2 h = \frac{22}{7} \times 7^2 \times 22.5 =3465 m^2$

The soil thus obtained is spread over a rectangular field of sides 21 m × 15 m to make a platform

Length of platform = 21 m

Breadth of platform = 15 m

Volume of dug = Volume of platform

$3465 = 21 \times 15 \times Height \\\frac{3465}{21 \times 15}=Height$

11 = Height

Hence The height of platform will be 11 m

#Learn more:

A well is dug 16 m deep. Its radius is 1.75. The earth dug out spread evenly on a rectangular platform which is 11 m × 4 m. Find the height of the platform raised.

https://brainly.in/question/2164350