Question

The wheel of an engine is of radius 2.8 meterfind the distance covered by it when it has made 100 revolutions

Answer 1

Distance covered in one rotation= circumference

Circumference= 2*pi*r

$= 2 \times \frac{22}{7} \times 2.8$

$= 17.6m$

Distance covered in 100 rotations= circumference*100

$= 17.6 \times 100$

$= 1760m$

Answer 2

Circumference = 2πr

= 2 x 22/7 x 2.8

= 2 x 22 x 0.4

= 17.6 m

Distance = no of revolutions x circumference

= 100 x 17.6

= 1760 m.

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