Question

The whole surface area of a rectangular block is 8788 cm.If the length breadth and height are in the ratio of 4:3:2 find difference between its length and height​

Answer 1

Answer:

the length breadth and height are in the ratio of 4:3:2...

this implies length=4x breadth=3x and height =2x

ATQ

TSA of cuboidal block = 2(lb+bh+hl) = 8788 cm²

put the values..

we get

2(4x3x + 3x2x + 2x4x) = 8788

12x² + 6x² +8x² = 4394

26x² = 4394

x² = 169

x = 13cm

this implies

length = 4x = 4 × 13 = 52cm

and height = 2x = 2 × 13 = 26cm

then

difference between its length and height

= 52 -26 = 26cm

hope this will help you

Answer 2

Step-by-step explanation:

26cm is answer