Question

the whole surface of a right circular cylinder is 10 sq m and the height is three times the radius of the base . find the radius of the base​

Answer 1

$let \: radius \: be \: x \\ height = 3x$

$total \: suface \: area = 2\pi \: r \: h \\ 10 = 2 \times \frac{22}{7} \times x \times 3x \\ 4x = \frac{10 \times 7}{2 \times 22} \\ x = \frac{70}{44 \times 4} = \frac{35}{88}$

$radius = \frac{35}{88}$

$height = 3 \times \frac{35}{88} = \frac{105}{88}$