Question

The wid pom of the line segment joing
(sin 90°, c050), (sec60, coseco) is​

Answer 1

Question :-

Find the mid point of line joining the point

( sin 90° , cos 0° ) and ( sec 60° , cosec 30°)

Answer :-

Mid point = 3/2,3/2

Solution :-

Let mid point is (x,y)

Using mid point formula

$\to \: x = \frac{ \sin90 \degree + \sec60 \degree}{2} \: ,\: y = \frac{ \cos 0 \degree + \cosec30 \degree}{2} \\ \\ \to \: x = \frac{1 + 2}{2} \: , \: y = \frac{1 + 2}{2} \\ \\ \to \: x = \frac{3}{2} \:, \: y = \frac{3}{2}$

Hence mid point is (3/2,3/2)

Answer 2

Answer:

Question :-

Find the mid point of line joining the point

( sin 90° , cos 0° ) and ( sec 60° , cosec 30°)

Answer :-

Mid point = 3/2,3/2

Solution :-

Let mid point is (x,y)

Using mid point formula

\begin{lgathered}\to \: x = \frac{ \sin90 \degree + \sec60 \degree}{2} \: ,\: y = \frac{ \cos 0 \degree + \cosec30 \degree}{2} \\ \\ \to \: x = \frac{1 + 2}{2} \: , \: y = \frac{1 + 2}{2} \\ \\ \to \: x = \frac{3}{2} \:, \: y = \frac{3}{2}\end{lgathered}

→x=

2

sin90°+sec60°

,y=

2

cos0°+cosec30°

→x=

2

1+2

,y=

2

1+2

→x=

2

3

,y=

2

3

Hence mid point is (3/2,3/2)