Math, asked by jayasudhaR, 11 months ago

the width if sidhar's gradens is 3/4 of its length. if it's perimeter is 40 metre. find the dimension help​

Answers

Answered by srishtipriya27
2

Answer:

L = 80/7m.

B = 60/7m.

Given: B = 3/4 L.-------(I)

P = 40m.

Step-by-step explanation:

Perimeter of the garden = 2 ( l+b ) = 40m.

= 2 ( l + 3/4 l ) = 40m.

= 2 * 7/4 l = 40m.

= 7/2 l = 40m

= l = 40 * 2/7 = 80/7m.

Putting the value of length in equation (I).

B = 3/4 L.

B = 3/4 * 80/7.

= 60/7 m.

Answered by george0096
3

Answer:

Length of Sidhar's garden = x m = 11.42m

Width of Sidhar's garden = ¾x m = (¾×11.42)m = 8.56m

Step-by-step explanation:

Let the length of the garden be x m and breadth be ¾x m.

Then, A/q

2(l+b) = 40m

2(x+¾x) = 40m

2x+\frac{3}{2}x = 40m

\frac{4x+3x}{2} = 40m

\frac{7}{2}x = 40m

7x = (40×2)m

7x = 80m

x = \frac{80m}{7}

x = 11.42m

Hence, the length of Sidhar's garden = x m = 11.42m

and width of Sidhar's garden = ¾x m = (¾×11.42)m = 8.56m

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