The width of a circular track is 2 meters. If the radius of the outer circle is 6 meters, find the area of the track in pi terms
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Answer:
Let radius of the outer circle = R m
and radius of the inner circle = r m
Now, 2πR=220
⇒2×
7
22
×R=220
∴R=
2×220
220×7
=35m
∴ Width of the track =7m
r=35−7=28m
Area of the circular track =π(R
2
−r
2
)
=
7
22
(35
2
−28
2
)
=
7
22
×(35+28)(35−28)
=
7
22
×63×7=1386m
2
∵ Rate of levelling the track=Rs.0.50/m
2
∴ Cost of levelling the track
=Rs.0.50×1386=Rs.693.
Answered by
0
Answer:
That's your answer little one.
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