Question

The width of a door is 40 cm. If it is released by exerting a force of 2 N at its edge (away from the hinges).Compute the moment of force produced which causes the door to open.

Answer 1

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Answer :

Force applied = F = 2 N

Force applied = F = 2 NLength of lever arm = d = 40 cm

Force applied = F = 2 NLength of lever arm = d = 40 cmTorque = 0.40 m (as distance amid the line of action of force and axis of rotation is 40 cm)

Force applied = F = 2 NLength of lever arm = d = 40 cmTorque = 0.40 m (as distance amid the line of action of force and axis of rotation is 40 cm)Torque = F × d

Force applied = F = 2 NLength of lever arm = d = 40 cmTorque = 0.40 m (as distance amid the line of action of force and axis of rotation is 40 cm)Torque = F × d= 0.40 × 20

Force applied = F = 2 NLength of lever arm = d = 40 cmTorque = 0.40 m (as distance amid the line of action of force and axis of rotation is 40 cm)Torque = F × d= 0.40 × 20Torque = 8 Nm.

Answer 2

Answer:

Force applied = F = 2 N

Length of lever arm = d = 40 cm

Torque = 0.40 m (as distance amid the line of action of force and axis of rotation is 40 cm)

Torque = F × d

= 0.40 × 20

Torque = 8 Nm.