Math, asked by tejanoralph14, 4 months ago

the width of a rectangle in 6cm shorter than its length. Find the possible length id the area of the rectangle is at least 667 square centimeter.

Answers

Answered by piyush433062
5

Step-by-step explanation:

hope it will help you bro

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Answered by payalchatterje
0

Answer:

The possible length of the rectangle is 29 cm.

Step-by-step explanation:

Given,the width of a rectangle in 6 cm shorter than its length.

Let length of the rectangle be x cm and according to question width of the rectangle be (x-6) cm.

It is given that area of the rectangle 667 square centimetre.

We know, area of a rectangle = length × width

For example,

If length of a rectangle is 8 m and width of the rectangle is 4 m then area of the rectangle

 = 8 \times 4 = 24 \:  {m}^{2}

According to question,

x(x - 6) = 667 \\  {x}^{2}  - 6x = 667 \\  {x}^{2}  - 6x - 667 = 0 \\  {x}^{2}  - 29x + 23x - 667 = 0 \\ x(x - 29) + 23(x - 29) = 0 \\ (x - 29)(x + 23) = 0

We know if product of two term is zero then they are separately zero.

So,

x - 29 = 0 \\ x = 29

and

x + 23 = 0 \\ x =  - 23

Side of a rectangle minus is not possible.

So, length of the rectangle is 29 cm and width of the rectangle (29-6) = 23

Rectangle related two more questions:

https://brainly.in/question/22537731

https://brainly.in/question/34004368

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