Question

The width of a rectangle is 16cm. If the perimeter of the rectangle is 80cm, find its length and its area

Answer 1

Length = x

Breadth = 16 cm

Perimeter = 80 cm

Perimeter of Rectangle = 2 ( l + b )

2 ( l + b ) = 80

2 ( x + 16 ) = 80

x + 16 = 80 / 2

x + 16 = 40

=> x = 40 - 16 = 24

Hence length of the rectangle is 24 cm.

Area of rectangle = Length * Breadth

=> Area = 24 * 16 = 384 cm²

Hence length = 24 cm and Area = 384 cm²

Answer 2

$\huge\underline\mathrm{SOLUTION:-}$

Given:

• The width of a rectangle is 16cm.
• The perimeter of the rectangle is 80 cm.

Need To Find:

• Length of the rectangle =?
• Area of the rectangle =?

ExPlanation:

• The width of a rectangle is 16cm. [Given]
• The perimeter of the rectangle is 80 cm. [Given]

We know that:

• Perimeter of the rectangle = 2 ( length + breadth)

1st Case:

• We have to find the length of the rectangle,

So,

Let the length of the rectangle be x.

As we know that,

• Perimeter of the rectangle = 2 ( length + breadth)

Substituting the values in the above formula, we get,

➠ 2 ( l + b ) = 80

➠ 2 ( x + 16 ) = 80

➠ x + 16 = 80 / 2

➠ x + 16 = 40

➠ x = 40 - 16

➠ x = 24

Now, We know that the value of x = 24.

• Therefore, length of the rectangle = 24 cm.

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2nd Case:

• We have to find the Area of rectangle,

It is Given that,

• Breadth of the rectangle = 16 cm.
• Length of the rectangle = 24 cm

Now,

We know that,

• Area of rectangle = Length × Breadth

Substituting the values in the above formula, we get,

= 24 × 16

= 384

• Therefore, Area of the rectangle = 384 cm².

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