Question

The width of a rectangle is 3 4 the length. The perimeter is 252 cm. What is the width of the rectangle?

Answer 1

Let the length be x cm
width is
$width \: is \: \frac{3}{4} x \\ perimeter \: = 2(l + b) \\ 252 = 2(x + \frac{3}{4}x) \\ \frac{252}{2} = x + \frac{3}{4}x \\ 126 = \frac{4x + 3x}{4} \\ 126 \times 4 = 7x \\ x = \frac{126 \times 4}{7} \\ x = 18 \times 4 \\ x = 72$
the length is 72 cm
$width = \frac{3}{4} x = \frac{3}{4} \times 72 \\ = 54 \: cm$

Answer 2

Hlo mate :-

Solution :-

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● Perimeter of rec = 2 ( l + b )

puting those values into your formula and solve for x:

252=2(x)+2(3/4)x

252=2x+6/4x

252=2x+3/2x

252=(4/2)x+(3/2)x

252=(7/2)x

2(252)=2(7/2)x

504=7x

504/7=x

72=x

Length: x=72 cm

Width:(3/4)(72)= 54 cm ans

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