Question

The width of a rectangle is 3 feet less than its length. the perimeter of the rectangle is 110 feet. find its dimensions.

Answer 1

2(l+b) =110
(L+b) = 55
And B=L-3
Therefore L+L-3=55
2L=58
L=29 feet
B=L-3
= 29-3
=26feet
Thus Length is 29 feet and breadth is 26 feet
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Answer 2

Answer: - Length = 29 feet and Breadth = 26 feet.

Detailed solution: -

Given: -

Perimeter of the rectangle = 110 feet

The width of a rectangle is 3 feet less than its length.

So,

We will let the length of the triangle be x feet.

Therefore,

The breadth of the rectangle will be = 3 feet less than its length = x - 3 feet

Now,

We will use the perimeter of the rectangle formula, i.e., perimeter of the rectangle = 2 (length + breadth) and find the value of x. Then we will find the dimensions using the value of x that we will get after solving the equation made.

Therefore,

Perimeter of the triangle = 2 (length + breadth)

110 feet = 2 (x + x - 3)

110 feet = 2 (2x - 3)

(We will multiply 2 with 2x and -3 to bring them out of the bracket.)

110 feet = $2*2x -3*2$

110 feet = 4x - 6

(-6 will shift to the left side of the equal to sign and the sign will change to +)

110 + 6 feet = 4x

116 feet = 4x

(Now, 4 will shift to the left side of the equal to sign anf will divide 116)

$116/4feet=x$

29 feet = x

Therefore,

The value of x = 29 feet.

Now we will find the dimensions.

The length of the rectangle = x feet

= 29 feet

And,

The breadth of the rectangle = x - 3 feet

= 29 - 3 feet

= 26 feet

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