Question

The width of a rectangle is 7 meters less than the length Find the dimension of the rectangle if the area is 369 square meters

Answer 1

Answer:

Let, The length of rectangle = x m

Breadth of rectangle = (x-7) m

Area of rectangle = length × breadth

or, 369 = x (x-7)

or, x^2-7x-369 = 0

or, x^2-2×x×(7/2)+(7/2)^2-369-(49/4) =0

or,

${(x - \frac{7}{2} ) }^{2} - (369 + \frac{49}{4} ) = 0$

or,

${(x - \frac{7}{2} )}^{2} = \frac{1525}{4}$

or,

$x = \frac{7}{2} + \frac{ \sqrt{1525} }{2}$

Hence, Length and Breadth of rectangle are

$\frac{7 + \sqrt{1525} }{2} m \: and \: \frac{ - 7 + \sqrt{1525} }{2} m$

respectively...