Question

The width of a rectangle is four-fifth it's length. If the perimeter of the rectangle is 90m. Find the length and breadth of the rectangle.​

Answer 1

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Length is L

Length is LWidth is 4/5 L

Length is LWidth is 4/5 LP = 90 = 2L + 2 (4/5 L)

Length is LWidth is 4/5 LP = 90 = 2L + 2 (4/5 L)90 = 2L + 8/5 L

Length is LWidth is 4/5 LP = 90 = 2L + 2 (4/5 L)90 = 2L + 8/5 L720 = 10 L + 8 L

Length is LWidth is 4/5 LP = 90 = 2L + 2 (4/5 L)90 = 2L + 8/5 L720 = 10 L + 8 L720 = 18 L

Length is LWidth is 4/5 LP = 90 = 2L + 2 (4/5 L)90 = 2L + 8/5 L720 = 10 L + 8 L720 = 18 LL= 720/18 = 40 m

Length is LWidth is 4/5 LP = 90 = 2L + 2 (4/5 L)90 = 2L + 8/5 L720 = 10 L + 8 L720 = 18 LL= 720/18 = 40 mW = 4/5 × 40 = 160/5 = 32 m

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Answer 2

Let the length of the rectangle be x

Then the breadth of the rectangle= 4/5 * x=4x/5

The perimeter of rectangle= 2(l+b)

= 2(x+4x/5)

=2(9x/5)

= 18x/5

Perimeter of rectangle = 18x/5=90m

18x=90*5

x=(90*5)/18

x=25

The length of the rectangle=x=25m

And the breadth of the rectangle=4/5*x=20m