Math, asked by Kavya7897, 5 months ago

The width of a rectangle is one third its length. If the area of the rectangle is 192 meters, find the dimensions of the rectangle.​

Answers

Answered by Anonymous
3

Answer:

To Find :-

Dimensions

SoluTion :-

As we know that

Area of rectangle = Length × Breadth

Let the length be x and breadth be x/3

192 = x × x/3

x × x = x²

192 = x²/3

x² = 192 × 3

x² = 596

x = √(596)

x = 24 m

Hence :-

Length is 24 m and breadth is 24/3 = 8 m

Extra Info :-

Perimeter of rectangle = 2(l + b)Diagonal of rectangle = √(length + breadth)Area of square = side²Diagonal of square = √2 × sidePerimeter of square = 4 × side

Answered by ADARSHBrainly
24

Correct Question :-

The width of a rectangle is one third its length. If the area of the rectangle is 192 meter square, find the dimensions of the rectangle.

Assumption :-

  • Let a be the length of rectangle

Given :-

  • Length of rectangle = a
  • Width of rectangle = \frac{1}{3}l
  • Area of rectangle = 192 m².

To find :-

  • Dimensions of rectangle means
  • Length and Breadth of rectangle.

Solution :-

We know that Area of Rectangle is given by

\underline{ \boxed{\sf{ \rightarrow{Area  \: of  \: rectangle = Length \times Breadth}}}}

Substituting the value in formula for finding value of a

{\sf{ \longmapsto{192 = a \times  \cfrac{1}{3} \:  a }}}

{\sf{ \longmapsto{192  = a \times  \cfrac{a}{3}  }}}

{\sf{ \longmapsto{192  =  \cfrac{ {a}^{2} }{3}  }}}

{\sf{ \longmapsto{192  \times 3 =  {(a)}^{2}  }}}

{\sf{ \longmapsto{576 =  {(a)}^{2}  }}}

{\sf{ \longmapsto{a =  \sqrt{576} }}}

{ \underline{ \boxed{ \blue{\sf{ \longmapsto{a =  24 }}}}}}

Here we have 24 as value of a.

Length of the rectangle is :-

\large{ \implies{\sf{\ Length = a }}}

{ \underline{ \boxed{ \red{\large{ \implies{\sf{\ Length = 24 \: m \:  }}}}}}}

Breadth of the Rectangle is :-

\large{ \implies{\sf{\ Breadth  =  \cfrac{1}{3} \:  a }}}

\large{ \implies{\sf{\ Breadth  =  \cfrac{1}{3} \:  \times 24 }}}

\large{ \implies{\sf{\ Breadth  = 1 \times 8 }}}

{ \underline{ \boxed{ \red{\large{ \implies{\sf{\ Breadth  = 8  \: m \: }}}}}}}

Similar questions