the width of a rectangle is three-fourth of its length. find the dimension of a rectangle if its perimeter is 28m
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Answer:
let length =l and breadth/width=b and perimeter =p
therefore, b=3l/4
2(l+b)=P
2(l+3l/4)=28
2{(4l+3l)}/4=28
2×7l=28×4
l=(28×4)/(7×2)
l=8
so, since l=8 b=(3×8)÷4=6
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