Question

the width of a rectangle is two - third of its length if the perimeter is 90 meters find the dimensions of the rectangle​

Answer 1

Answer:

Let the length be x

so , width = 2x/3

Perimeter of rectangle = 2(l+b)

$2(x + \frac{2x}{3} ) = 90 \\ 2( \frac{3x + 2x}{3} ) = 90 \\ 2( \frac{5x}{3} ) = 90 \\ \frac{5x}{3} = \frac{90}{2} \\ 5x = 45 \times 3 \\ x = \frac{45 \times 3}{5} \\ x = 9 \times 3 \\ x = 27 \\ width \: = \frac{2 \times 27}{3} \\ = 18m$

Hence, length of rectangle is 27 m

and width is 18 m

Answer 2

Step-by-step explanation:

let the length of rectangle=x

then the breadth of rectangle=2x/3

perimeter of the rectangle=90m

2(x+2x/3)=90m

2(5x/3)=90m

2×5x/3=90m

10x/3=90m

10x=90×3

x=90×3/10

x=27m

length of the rectangle=27m

breadth of the rectangle=27×2/3

= 54/3

= 18m

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