Question

The width of a rectangle is two-thirds its length. If the perimeter is 180m, find the

dimensions of the rectangle.

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Answer 1

Answer:

Let the length of the rectangle be x

Width of the rectangle = 2/3x

Perimeter of rectangle = 2(l+b)

= 2(x+2/3x) = 180

=> 2( 5/3x) = 180

=> 5/3x = 180/2 = 90

=> x = 90×3/5

=> x = 54

Therefore the length of rectangle = 54m

Width of rectangle = 2/3 × 54 = 36m

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Answer 2

$let \: the \: length \: be: n \: metres \\ so \: width: \frac{2}{3}n \: metres \\ \\ (as \: we \: know): \\ \\ perimeter \: of \: a \: rectangle \: = \\ 2(l + b) \: units \\ \\ so \: now: \\2 (n + \frac{2}{3}n) = 180 \\ 2n + \frac{4}{3}n \: \: \: \: = 180 \\ \frac{6n + 4n}{3} \: \: \: \: = 180 \\ 10n \: \: \: \: \: \: \: \: \: \: \: \: \: = 180 \times 3 \\ n \: \: \ \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{180 \times 3}{10}= 54m \\ \\ now \: length = 54m \: \\ and \: width \: \: = 54 \times \frac{2}{3} = 36m \\ \\ \\ \\ \\ hope \: it \: helps \: you...$

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