Question

The width of a rectangle is two-
thirds its length. If the perimeter is
180 metres, find the length. *
45
54
50
56
The rectangle's breadth will be *
30
35
33
36
*
in the above rectangle , if the breadth is increased by 18 which figure will be formed
*square
triangle
pentagon

if 5/4 parts of length is taken and 7/8 parts of the breadth is taken the new perimeter will be*

146.8

148.6

147.9

149.4

Find The area of new rectangle*

1345.9

1360.8

1367.3

1354.5​

Answer 1

Answer:

(i) Length = 54m

(ii) Width = 36m

(iii) Rectangle

(iv) If length is taken 5/4,Perimeter = 203m

If length is taken 4/5 , Perimeter = 146.6m

(v) Area of the Rectangle = lb = 44.8 × 31.5 = 1411.2 m²

Step-by-step explanation:

Given, the relation between width(b) and length(l) is

2/3rd of l = b

Perimeter of the rectangle = 2(l + b) Given as 180m

So, (l + b) = 90m

=> (l + 2L/3) = 90

=> 5L/3 = 90

=> L = (90 × 3) ÷ 5 = 54m

Breadth = 2/3 of L = (2 × 54) ÷ 3 = 36

If the breadth is decreased by 18m, then it will form another rectangle of length 56 and width (36 - 18) = 18m

If length is taken 5/4 and breadth taken 7/8, then

Length = 56 × 5/4 = 14 × 5 = 70m

Breadth = 36 × 7/8 = 31.5m

Perimeter = 2( l + b ) = 2(70 + 31.5) = 203m

If length is taken 4/5 and breadth taken 7/8, then

Length = 56 × 4/5 = 44.8m

Breadth = 36 × 7/8 = 31.5m

Perimeter = 2( l + b ) = 2(44.8 + 31.5) = 146.6m

Area of the Rectangle = lb = 44.8 × 31.5 = 1411.2 m²