The width of a rectangle is two - thirds its length . if the perimeter is 180 m find its dimensions
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Answered by
19
Heya ✋
Let see your answer !!!
Let the length of a rectangle be (x)m. Then,
width of a rectangle = (2x/3)m.
Perimeter = 180m
Perimeter of a rectangle = 2(l + b)
=> 180 = 2(x + 2x/3)
=> 180/2 = (3x + 2x/3)
=> 90 = 5x/3
=> x = 90 × 3/5
=> x = 54
Hence , the length = 54m
and width = (2 × 54/3)m
= 36m
Thanks :))))
Let see your answer !!!
Let the length of a rectangle be (x)m. Then,
width of a rectangle = (2x/3)m.
Perimeter = 180m
Perimeter of a rectangle = 2(l + b)
=> 180 = 2(x + 2x/3)
=> 180/2 = (3x + 2x/3)
=> 90 = 5x/3
=> x = 90 × 3/5
=> x = 54
Hence , the length = 54m
and width = (2 × 54/3)m
= 36m
Thanks :))))
Answered by
16
Length of the rectangle= x
Width of the rectangle= 2/3x
Perimeter= 2(l+b)
So, 2(x+2/3x)= 180m
x+2x/3= 180/2= 90
x+2x/3= 90
5x/3= 90
x= (90*3)/5
x= 54m
Length of the rectangle= 54 m
Breadth of the rectangle= (2/3)*54= 36 m
HOPE IT HELPS
MARK ME AS THE BRAINLIEST PLZZZZ
Width of the rectangle= 2/3x
Perimeter= 2(l+b)
So, 2(x+2/3x)= 180m
x+2x/3= 180/2= 90
x+2x/3= 90
5x/3= 90
x= (90*3)/5
x= 54m
Length of the rectangle= 54 m
Breadth of the rectangle= (2/3)*54= 36 m
HOPE IT HELPS
MARK ME AS THE BRAINLIEST PLZZZZ
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