The width of a rectangle is two-thirds of its length.if the perimeter of the reactangle is 80m. find its area
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Answered by
91
Given :-
- The width of a rectangle is two-thirds of its length.if the perimeter of the reactangle is 80m.
To Find :-
- Area of rectangle
Solution :-
Let the length be x m and breadth be y m
then,
➦ According to the Question
- Perimeter of rectangle = 80m
➪ 2(length + breadth) = 80
➪2(x + 2x/3) = 80
➪ (2x + 2x/3) = 80/2
➪ 4x/3 = 40
➪ x = 40 × 3/4
➪ x = 10 × 3
➪ x = 30
Hence,
- Length of rectangle = x = 30m
- Breadth of rectangle = 2x/3= 20m
Now, area of rectangle
➪ length × breadth
➪ l × b
➪ 30 × 20
➪ 600m²
Therefore,
- Area of Rectangle = 600 m²
Answered by
51
The width of a rectangle is two-thirds of its length.if the perimeter of the Rectangle is 80m. Find its area ..
_______________
✒Given : -
- The width of a rectangle is two-thirds of its length...
- Perimeter of the Rectangle is 80 m ..
✒To Find : -
- Area of the Rectangle = ?
✒Formula Used : -
✒Let ,
- Length of the rectangle = y
- Then, Breadth will be = 2y/3
✒On Substituting Values : -
✒Therefore , Length of Rectangle is 30m ..
✒Hence ,
✒Formula Used : -
→ So , the Area of Rectangle is 600m² ..
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