Question

the width of a rectangle is two- thirds of its length if the perimeter is 180 M find the dimension of a rectangle

Answer 1

let the length be x
then width is x/3
perimeter of a rectangle=2(l+b)
180m=2(x+x/3)

8x/3=180m
x=(180×3)/8=....
now plzz calculate ...

Answer 2

◆Hello dear,
______________________________
Let the length(l) be x.

So,

•Width of rectangle(b) = 2x/3

●Given,
•Perimeter of rectangle = 180 m

●Now,
•Perimeter of rectangle = 2(l + b)
$180 = 2(x + \frac{2x}{3} ) \\ 180 = 2( \frac{3x + 2x}{3} ) \\ 180 = 2 \times \frac{5x}{3} \\ 180 = \frac{10x}{3} \\ x = \frac{180 \times 3}{10} \\ x = 18 \times 3 \\ x = 54$
●Hence,

•Length of rectangle = x = 54 cm
•Width of rectangle = 2x/3 = (2*54)/3 = 108/3 = 36 cm

Hope it helps!