Question

The width of a rectangle is y feet long. The rectangle is 4 feet longer than it is wide. What is the area of the rectangle?
Which expression represents the area?
y(y + 4) sq ft
y + 4 sq ft
4y sq ft

Answer 1

Given :

• The width of a rectangle is y feet long.
• The rectangle is 4 feet longer than it is wide.

To find :

• The area of the rectangle =?

Formula Used :

• Area of Rectangle = length × breadth

Step-by-step explanation :

It is Given that,

The width of a rectangle is y feet long.

And,

The rectangle is 4 feet longer than it is wide.

So,

The length of the rectangle = y + 4.

As We know that,

Area of Rectangle = length × breadth

Substituting the values in the above formula, we get,

= y × y + 4

= y(y+4)

Therefore, y(y + 4) sq ft expression represents the area.

Answer 2

${ \rm{ \huge{ \underline{QUESTION }}}}$



▪ The width of a rectangle is y feet long . The rectangle is 4 feet longer than its width. What is the area of the rectangle ?
Which expression represents the area???

(a) y (y+4) sq.ft

(b) (y + 4) sq. ft

(c) 4y sq. ft




${ \rm{ \huge{ \underline{SOLUTION }}}}$




${ \blue{ \bold{ GIVEN }}}$



${ \sf{ \green{width = y \: feet}}}$



${ \star{ \sf{ \: \: length \: is \: 4ft \: longer \: than \: width}}} \\ \\ { \sf{then}} \\ \\ { \sf{ \green{length = (y + 4) \: feet}}}$



${ \blue{ \bold{TO \: FIND }}}$




${ \rightarrow{ \sf{area \: of \: the \: rectangle}}}$



${ \boxed{ \boxed{ \red{ \sf{ \: \: area = length \times width \: \: }}}}}$



${ \implies{ \underline{ \red{ \sf{area = (y + 4) \times y \: sq. \: ft}}}}}$




${ \sf{hence}} \\ \\ { \sf{ \blue{option \: (a) \: (y + 4)y \: sq. \: ft \: is \: correct}}}$