Question

The width of a rectangular field is 2/3 of its length. Find its dimensions if the perimeter of the field is 220 m.​

Answer 1

Answer:

44,66

Step-by-step explanation:

width = 44 length = 66

Answer 2

Answer:

Let the length = x

So, breadth= 2/3x

ATQ

2($x+\frac{2x}{3}$)=220

$\frac{3x+2x}{3}$=220

5x=660

x=132

So length= 132 m

and breadth = 88 m

Step-by-step explanation: