Question

the width of a rectangular field is three fourth of its length if the area of a field is 588 square metre then find its perimeter

Answer 1

Solutions :-

Let the length be x
Width = ¾ of x = ¾x

Given : Area of rectangular field = 588 m²

According to the question,

=> x × ¾ x = 588
=> 3x²/4 = 588
=> 3x² = 588 × 4
=> 3x² = 2352
=> x² = 2352/3 = 784
=> x = √784 = 28

Therefore,
Length = x = 28 m
Width = ¾x = ¾ × 28 = 21 m

Find the perimeter of rectangular field :-

Perimeter = 2(Length + width) units
= 2(28 + 21) m
= 2 × 49 m
= 98 m

Hence,
Perimeter of rectangular field = 98 m

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✯ @shivamsinghamrajput ✯

Answer 2

$Hey\:!!..$

The answer goes here....

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》To find :

Perimeter of the rectangular area.

》Given :

Area of field = 588 ${m}^{2}$

》Solution :

Let the length of the rectangular field be $x$ .

Then, width of the rectangular field = $\frac{3}{4}x$

Now, according to the question,

$Area=Length\times width$

=> $588=x\times \frac{3}{4}x$

=> $588=\frac{{3x}^{2}}{4}$

=> $588\times={3x}^{2}$

=> ${x}^{2}=\frac{2352}{3}$

=> $x=28$

So, the length of the rectangle is 28 m.

Now,

Width = $\frac{3}{4}\times 28$

Width = 21 m

Therefore, the width of the rectangle is 21 m.

Also,

Perimeter = $2(l+b)$

Perimeter = $2(28+21)$

Perimeter = 98 m.

So, the perimeter of the rectangular field is 98 m.

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Thanks !!..