the width of a rectangular room is 4/7 of its length ,x,and its perimeter is y. Write an equation connecting x and y. find the length of the room when the perimeter is 4400cm
Answers
Answered by
41
y=2(x+4x/7)
y= 2x+8/7 x
y=14x+8x/7
y=22x/7---} equation...
y=4400
so,22x/7=4400
22x= 4400*7
x=4400*7/22
x=200*7
x = 1400
length =1400cm...
y= 2x+8/7 x
y=14x+8x/7
y=22x/7---} equation...
y=4400
so,22x/7=4400
22x= 4400*7
x=4400*7/22
x=200*7
x = 1400
length =1400cm...
mayank174:
with steps
i gave all steps to u
check answer properly
u were confusing at units
observe properly
my ans is in cm
ur ans is in m
no tell me
her answer is correct
1400 is in centimeter in metre is 14m
Answered by
20
Equation= y= 2(x +4/7*x)
Perimeter of rectangle 2(length+breadth)
4400=2(x+4/7×x)
4400=2(x+4x/7)
4400= 2x+8x/7
4400= 22x/7
4400*7= 22x
30800 = 22x
30800/22= x
1400 = x
Therefore x= 1400 is the solution of the equation.
As mentioned that the length is x and its vale is 1400
So, 1400 = length.
So the length is 1400 cm.
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hope it helps!
Perimeter of rectangle 2(length+breadth)
4400=2(x+4/7×x)
4400=2(x+4x/7)
4400= 2x+8x/7
4400= 22x/7
4400*7= 22x
30800 = 22x
30800/22= x
1400 = x
Therefore x= 1400 is the solution of the equation.
As mentioned that the length is x and its vale is 1400
So, 1400 = length.
So the length is 1400 cm.
----------------
hope it helps!
its wrong
from third step
yea thank you for telling me I came to know my mistake
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