Question

the width of circle track shown in the picture is 2 meter . if the radius of the outer circle 6,meter find the track (π=3)​

Answer 1

Answer:

Step-by-step explanation:

Let radius of outer circle be R= 6m

radius of inner circle be r=(6-2)=4m

Then,

Area of track= πR^2 -πr^2

=π(R^2 - r^2)

=3.14(6^2 - 4^2)

=3.14(36-16)

=3.14×20

=62.8m^2

Thats your answer

.....hope you got it!

Answer 2

Answer:

62.8^2

Step-by-step explanation:

Let radius of outer circle be R= 6m

radius of inner circle be r=(6-2)=4m

Then,

Area of track= πR^2 -πr^2

=π(R^2 - r^2)

=3.14(6^2 - 4^2)

=3.14(36-16)

=3.14×20

=62.8m^2