Question

The width of each of five continuous classes in a frequency distribution is 5 and the lower class limit of the lowest class is 10. What is the upper class limit of the highest class?
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Answer 1

$\huge\pink{ANSWER}$

⇒ Let x and y be the upper and lower class limit of frequency distribution.

⇒ width of the class = 5

⇒ x−y=5 ---- ( 1 )

⇒ Also, given lower class

y=10

. On putting

y=10

in Eq.( 1 ), we get,

⇒ x=15

⇒ So, the upper class limit of the lowest class is

15.

⇒Hence, the upper class limit of the highest class=(Number of continuous classes x Class width + Lower class limit of the lowest class)

5×5+10=25+10=35

⇒ The upper class limit of the highest class

∴ The upper class limit of the highest class is

35.

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