Question

the width of each of five continuous classes in a frequency distribution is 5 and lower class limit of the lowest class is 10 what is the upper limit of the highest class

Answer 1

Answer:

The upper limit of the highest class is 35

Step-by-step explanation:

It is given that,

The width of each of five continuous classes in a frequency distribution is 5 and lower class limit of the lowest class is 10

frequency distribution can be written as,

10 - 15

15 - 20

20 - 25

25 - 30

30 - 35

Therefore 35 is the frequency distribution

Answer 2

Answer:

35

Step-by-step explanation:

As per given information from frequency distribution, suppose

upper class limit = x

lower class limit = y

width of the classes = 5

So, from the above information we can write the following equation:

x-y= 5 ….....(i)

Also, it is given that

Lower limit of lowest class = y = 10

Now substituting y  =10 into equation (i), we get

x – 10= 5

x = 5 + 10

x =15

So,

upper class limit of the lowest class = 15.

Now, lets calculate the upper class limit of the highest class by using the following formula

upper class limit of the highest class

=(Number of continuous classes x Classes width + Lower class limit of the lowest class)

upper class limit of the highest class= 5 x 5 + 10 = 25 + 10=35

So, the upper class limit of the highest class is 35.

Method2

After we find the upper class limit of the lowest class, we can write the consective classes with width 5 as show below:

10     -   15

15     -   20

20    -    25

25    -    30

 30   -    35

As we can see from the above distribution, the highest class is 30-35,  and

the upper limit of this class is 35