The width of Madhu's garden is 2/3 of its length.If its perimeter is 40 m. Find its dimensions.
Answers
Step-by-step explanation:
Given:-
The width of Madhu's garden is 2/3 of its length. Its perimeter is 40 m.
To find :-
Find its dimensions ?
Solution :-
Let the length of the garden be X m
Then , the width of the garden = 2/3 of the length
=> (2/3) of X
=> (2/3)×X
=> (2×X)/3
=> 2X/3 m
We know that
Perimeter of a rectangle = 2 (l+b) units
Perimeter of the given garden
=> 2[X+(2X/3)]
=> 2[(3X+2X)/3]
=> 2(5X/3)
=> 10X/3
Therefore, Perimeter = 10X/3 m
According to the given problem
Perimeter of the garden = 40 m
=> 10X/3 = 40
=> 10X = 40×3
=> 10X = 120
=> X = 120/10
=> X = 12
The length = 12 m
Width = 2X/3 = (2×12)/3 = 24/3 = 8 m
Therefore, Length = 12 m , width = 8 m
Answer:-
The dimensions of the garden are 12 m and 8 m
respectively.
Used formulae:-
→Perimeter of a rectangle = 2 (l+b) units
Where , l = length
and b = breadth or width
Answer:
Length = 12 meters
Breadth = 8 meters
Step-by-step explanation:
Let the length of garden = X meter
then , breadth = 2/3 of X meter
perimeter = 40 meter
perimeter of garden = 2 ( L + b )
=> 40 = 2 ( X + 2/3 × X )
=> 40 = 2 ( X + 2X /3 )
=> 40 = 2 × 5X /3
=> 5X /3 = 40/2
=> 5X / 3 = 20
=> 5X = 20 × 3
=> 5X = 60
=> X = 60/ 5
=> X = 12 meters
so ,
The length of garden = 12 meters
and the breadth = 12 × 2/3 = 8 meters
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