Question

The width of Ram's ground is 4 / 5 of its length. if its perimeter is 80 m, find its dimensions

Answer 1

$\huge{\mathfrak {\red{Q}{\underline{\underline{uestion}}}}}$



The width of Ram's ground is 4/5 of is length. If its perimeter is 80 m, find its dimensions.


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${ \red{\mathfrak{\huge{A}}}}{\underline {\underline{\mathfrak{\huge{nswer}}}}}$




→$\underline{ \underline {\mathfrak {Length = 22.23 \: m }}}$

→$\underline{ \underline {\mathfrak {Breadth = 17.784 \: m }}}$




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$\huge\mathfrak \pink{ \overline{ \underline{ \: Brainliest \: Answer \: }}}$




${ \sf Let, Length \: be \:} x \sf\: m \\ {\sf Then,} \: \frac{4}{5} x \: \sf m \\ \\ \sf Perimeter = 2(length × breadth) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = { \sf 2} \bigg(x + { \sf \frac{4}{5} }x \bigg) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = { \sf2}x + { \sf\frac{8}{5} }x \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: By \: the \: given \: condition, \\ \\ \\ \implies 2x + \frac{8x}{5} = 80 \\ \implies 10x \: + 8x = 400 \\ \implies 18x = 400 \\ \implies x = \frac{400}{18} = 22.23 \\ \\ \\ \therefore \sf Length \: is \: { \bf {\red {22.23 \:m }}}\: and \: {\sf width \: is }\: \frac{4}{5} \: × \: 22.23 \: = { \bf \red{ \: 17.784 \: m }}$



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$\huge \orange{ \boxed{ \boxed{ \sf{ \therefore \: Length = 22.23 \: m}}}}$




$\huge \orange{ \boxed{ \boxed{ \sf{ \therefore \: Breadth = 17.784 \: m}}}}$




✔✔ Hence, it is solved ✅✅




$\huge \blue{ \boxed{ \boxed{ \mathscr{THANKS}}}}$

Answer 2

Let Length=X

Then Breadth is =$\frac{4}{5}$ of Length.

Breadth=$\frac{4}{5}\timesx$

Perimeter=2(L+B)

A/Q

$2(x + \frac{4x}{5} ) = 80 \\ \\ 2( \frac{4x + 5x}{5} ) = 80 \\ \\ 2 \times \frac{9x}{5} = 80 \\ \\ x = 80 \times \frac{5}{9 \times 2} \\ \\ x = \frac{200}{9} m$

Length=$\frac{200}{9}\:m$

$breadth = \frac{4}{5} \times \frac{200}{9} \\ \\ = \frac{160}{9} m$

$\boxed{\mathbf{Length=\frac{200}{9}\:m}}$

$\boxed{\mathbf{Breadth=\frac{160}{9}\:m}}$