Math, asked by KKJIII, 1 year ago

The width of Ram's ground is 4 /5 of its length. if its perimeter is 80 m, find its dimensions

Answers

Answered by Anonymous
0
\huge{\mathfrak {\red{Q}{\underline{\underline{uestion}}}}}<br />



The width of Ram's ground is 4/5 of is length. If its perimeter is 80 m, find its dimensions.


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{ \red{\mathfrak{\huge{A}}}}{\underline {\underline{\mathfrak{\huge{nswer}}}}}




\underline{ \underline {\mathfrak {Length = 22.23 \: m }}}

\underline{ \underline {\mathfrak {Breadth = 17.784 \: m }}}




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 \huge\mathfrak \pink{ \overline{ \underline{ \: Brainliest \: Answer \: }}}




{ \sf Let, Length \: be \:} x \sf\: m \\ {\sf Then,} \: \frac{4}{5} x \: \sf m \\ \\ \sf Perimeter = 2(length × breadth) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = { \sf 2} \bigg(x + { \sf \frac{4}{5} }x \bigg) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = { \sf2}x + { \sf\frac{8}{5} }x \\ \\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: By \: the \: given \: condition, <br />\\ \\ \\ \implies 2x + \frac{8x}{5} = 80 \\ \implies 10x \: + 8x = 400 \\ \implies 18x = 400 \\ \implies x = \frac{400}{18} = 22.23 \\ \\ \\ \therefore \sf Length \: is \: { \bf {\red {22.23 \:m }}}\: and \: {\sf width \: is }\: \frac{4}{5} \: × \: 22.23 \: = { \bf \red{ \: 17.784 \: m }}



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\huge \orange{ \boxed{ \boxed{ \sf{ \therefore \: Length = 22.23 \: m}}}}




\huge \orange{ \boxed{ \boxed{ \sf{ \therefore \: Breadth = 17.784 \: m}}}}




✔✔ Hence, it is solved ✅✅




\huge \blue{ \boxed{ \boxed{ \mathscr{THANKS}}}}
Answered by bhattak9617
0
let the length be x
so, the breadth is
 \frac{4x}{5}
ATQ
perimeter = 80
2( l + b ) = 80
2(x + \frac{4x}{5}) = 80
 2x+\frac{8x}{5 } = 80
18x = 80×5
x = \frac{400}{18}
x = 22.22
length = x = 22.22m \\ breadth = \frac{4x}{5} = \frac{4 \times 22.22}{5 } \\ = \frac{88.88}{5} \\ = 17.78m \\ so... \\ length = 22.22m \\ breadth = 17.78m
hope it helps
mark Brainliest
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