Question

The width of Sanya’s garden is 2/3 of its length. If its perimeter is 40 metres, find the dimensions of the garden.

Please answer the question.

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Answer 1

Answer:

Given :

Perimeter of Garden = 40 m

Let the length of sanya's Garden = L

Width of sanya's Garden = B

ATQ

Width of sanya's Garden(B) = (⅔)L

Perimeter of Garden = 2(L + B)

40 = 2(L + ⅔ L)

40/2 = (3L +2L) /3

20 = 5L/3

20 × 3 = 5L

60 = 5L

L = 60/5

L = 12 m

Length = 12 m

B = ⅔ L

B =( ⅔) × 12 = 2 × 4 = 8 m

B = 8 m

Breadth = 8 m

Hence the dimensions of Sanya's garden is 12 m & 8m.

Answer 2

Answer:

Length = 12 m

Width = 8 m

2(x + 2/3x) = 40

x + 2/3x = 40/2

x + 2/3x = 20

5x/3 = 20

5x = 20 × 3

x = 60/5

x = 12

Length = x = 12 m

Width = 2/3x = 2/3 × 12 = 8 m

Explanation: