Question

The width of sudha's garden is 2/3 of its length if it's perimeter is 40 m find its dimensions

Answer 1

SOLUTION :
Given :
Perimeter of Garden = 40 m
Let the length of sudha's Garden = L
Width of sudha's Garden = B

ATQ
Width of sudha's Garden(B) = (⅔)L
Perimeter of Garden = 2(L + B)
40 = 2(L + ⅔ L)
40/2 = (3L +2L) /3
20 = 5L/3
20 × 3 = 5L
60 = 5L
L = 60/5
L = 12 m
Length = 12 m

B = ⅔ L
B =( ⅔) × 12 = 2 × 4 = 8 m
B = 8 m
Breadth = 8 m

Hence the dimensions of Sudha's garden is 12 m & 8m.

HOPE THIS WILL HELP YOU….

Answer 2

Let the length of her garden be x

So, width will be (⅔ of x)




We know, perimeter = 2(length + breadth)



Here, perimeter is given,


40 = 2( x + ⅔ of x)

40/2 = x + ⅔ × x

20 = x + 2x/3

20 = (3x + 2x)/3

20 × 3 = 5x

60 = 5x

60/5 = x

12 = x






Hence, length = x = 12 m
Breadth = ⅔ of x = ⅔ × 12 = 8 m