Question

The width of sudha's garden is two third of the garden. If its perimeter is 40 meter. Find its dimensions

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\huge\star{\sf{\red{To\:Find:-}}}$

• The dimensions of rectangle

$\bf\underline{\underline{\blue{According\:To\: Question:-}}}$

• Let the length of garden be x

• width =$\frac{2}{3} x$

$\boxed{\sf{Perimeter\:of\: rectangle=2(l+b)}}$

$\sf\implies 40=2(x+\frac{2x}{3})\\ \\ \sf\implies 40=2(\frac{3x+2x}{3})\\ \\ \sf\implies \cancel{\frac{40}{2}}=\frac{5x}{3}\\ \\ \sf\implies 20\times 3=5x\\ \\ \sf\implies 60=5x\\ \\ \sf\implies \cancel{\frac{60}{5}}=x\\ \\ \sf\implies x=12cm$

• The value of x is 12 cm which is the length of rectangle
• Now the width which is two third of length

$\sf\implies Width=\frac{2}{\cancel3}\times \cancel{12}\\ \\ \sf\implies width= 2\times 4\\ \\ \sf\implies width=8cm$

• Width =8cm

• Now let's verify our answer

$\tt\implies {\red {Perimeter=2(l+b)}}\\ \\ \sf\implies 40=2(12+8)\\ \\ \sf\implies 40=2\times 20\\ \\ \sf\implies 40=40\\ \\ \sf\:\:\:L.H.S=R.H.S\:\:\:\sf hence\: verified ! !$

$\boxed{\sf{\purple{Dimensions\:of\: rectangle= 12cm\:and\:8cm}}}$

#BAL

#answerwithquality