Question

The width of the track is 3.5 m than the radius of the inner circle is​

Answer 1

Answer:

below is the explanation

Step-by-step explanation:

The area of the inner circle with inner radius of 21m is pi r squared 3.1416*21^2= 1385.44 sq.m.

The area of the whole circle including the track is (21 + 3.5)^2*3.1416= 24.5^2*3.1416= 1885.74 sq.m.

so, the area of track is 1885.74–1385.44=500.3 sq.m.