Question

The wings of a mosquito vibrate 200 times in 5 seconds. Find its frequency and time period.

Answer 1

0.001 Is the answer

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Answer 2

Answer:

The frequency of the body is 40 Hz.

The time period of the body is 0.025 second.

Explanation:

Given,

The wings of a mosquito vibrate 200 times.

 The time taken for the mosquito to vibrate 200 times = 5 seconds

We know that frequency = vibration/ time taken

Frequency ⇒ 200/5

                   ⇒ 40

∴ The frequency of the body is 40 Hz.

We know that time period = time taken/ cycles(Vibration)

Time period ⇒ 5/200

                     ⇒ 1/40

                     ⇒ 0.025

∴ The time period of the body is 0.025 second.