Question

the wire is bent in the form of an equilateral triangle whose perimeter is 132 the same wire is re - bent to form a circle find the area enclosed by the circle​

Answer 1

Answer:

length of wire = perimeter of triangle = 3×4.4 = 13.2 cm

now

circumference of circle = length of wire

2πr = 13.2

r = 13.2×7/2×22

r = 2.1 cm

Area of circle = πr² = 22/7×(2.1)² = 13.86 cm²

Step-by-step explanation:

Answer 2

Step-by-step explanation:

Question :-

• The wire is bent in the form of an equilateral triangle whose perimeter is 132 the same wire is re - bent to form a circle find the area enclosed by the circle.

Solution :-

Length of wire = 3 × 4.4 = 13.2 Cm

Circumference of circle = Length of wire

$→ 2πr² = 13.2 cm$

$→ r \: = 13.2 × 7/2 × 22$

$→ r = 2.1 cm$

∴ Area of circle = πr² = 22/7 ( 2.1)² = 13.86 cm²

Answer :- 13.86 cm²