Question

The wires holding up an 11m ratio transmitter join 2m from the top of the aerial and are anchored to the ground 7m from the base of the aerial. How long are the wires?​

Answer 1

Answer:

Step-by-step explanation:

The set up of wire, mast and ground form a right angle triangle of sides

9m and 7 m.  The wire will form the hypotenuse of the triangle, call it x m

9^2 + 7^2 = x^2

81 + 49 = x^2

130 = x^2

x = $\sqrt 130$

= 11.4 m