Question

The wonder walls equations for a gas is (p+a/V2)(v-b) =RT. Determine the dimension of a and b hence write the si unit of a and b? please give me the answer​

Answer 1

Answer:

Dimension of 'a' is kg m^5 sec^(-2) and that of 'b' is m^3

Explanation:

For S.I. unit of "a"

$[P] = [\frac{a}{V^{2} } ]\\[a] = [ML^{-1}T^{-2}][M^{6}]\\[a] = [ML^{5}T^{-2}]$

For S.I. unit of "b"

$[b] = [V]\\[b] = [L^{3}]$