The work A can do in 20 days,B can do it in 12 days.After A having worked for some days B began to work in place of A,and the work was finished in 14 days.Find how many days A worked.
Answers
Answer:
Given,
A can do a work in 20 days.
=> In a single day, A will complete 1/20th part of the total work.
B can do a work in 12 days.
=> In a single day, B will complete 1/12th part of the total work.
So, if they both work together,
=> 1/20 + 1/12
=> 3/60 + 5/60
=> 8/60
=> 2/15
In a single day, A and B together will complete 2/15th part of the total work.
Now, let's move forward to what other things are given. A already worked for 5 days. So, the amount of work completed is
=> 5*(1/20)
=> 1/4.
As 1/4th of the work is already completed so now A and B have to complete the rest 3/4th of the work together. So, number of days required by both of them to complete the work will be
=> 1/((Work Left)*(Work completed in a single day))
=> 1/((3/4)*(2/15))
=> 1/(1/10)
=> 10 days.
The question is how long did the work last. As, A has already worked 5 days so the work lasted 5 days + 10 days = 15 days in total.
So, the correct answer will be 15 days.
Step-by-step explanation:
Answer:
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