Question

the work done and power of an engine that can maintain a speed of SO ms' for a train of mass 3 x 106 kg on a rough level track for 5 km. The coefficient of friction is 0.05. Given g = 10 ms?​

Answer 1

Explanation:

Given, Speed=50m/s,Mass=3×106kg

Coefficient=0.05,g=10m/s2

So, the frictional force act on it μN Where, N=mg

F=μmg=0.05×10×3×106=15×105N

Thus the power delivered  by thee train F×v=15×105N×50

=75×106J/s

Answer 2

Answer:

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