The work done by a force F =(-6
î) N in displacing a particle from x= 4 mto x=-2 m is
(A)-240 J
(B) 360 J
(C) 420 J
(D) will depend upon the path
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Answer:
Work done is 144 J.
Explanation:
Given,
The work done by a force F =(-6 x² î) N in displacing a particle from x= 4 m to x=-2 m.
Solution:
We know,
Work done = F. dx
or, ∫ dW = ∫ F.dx cos 0°
W = ∫₄⁻² 6x² dx
or, W = [ 6x³ / 3 ]₄⁻²
or, W = 2 [4³ - (-2)³ ]
or, W = 2 [ 64 + 8]
or, W = 2 * 72
or, W = 144 J
None of the option is 144 J. So either the options are incorrect or question is incorret.
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