Question

The work done by a force F = (-6x) i N, in
displacing a particle from x = 4 m to x = - 2 m is​

Answer 1

Answer:

-36J

Explanation:

Work done = Force.dx (where dx represents small change in distance)

$\\\tt W= \int F.dx\\\\\tt = \int_{-2}^{4} (-6x) dx\\\\\tt = [-\dfrac{6x^2}{2}]_{-2}^4\\\\\tt = [-3x^2]_{-2}^4\\\\\tt = -3(16-4)\\\\\tt = -3(12)\\\\\tt = -36$

Hence work done = -36J