Question

The work done by a Force F = (i +2j +3k) N, to displace a body from position A with position vector r1 = (i+3j+k)m to position B with position vector r2 = (2i +2j +3k)m is
a. 5J b. 3J c.2J d.10J

Answer 1

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Actually Welcome to the Concept of the Kinematics and Work Energy on a system.

Now basically here we, are talking about the work done by a body in the form of displacement.

This displacement is done due to the force that acted upon the body.

To calculate the work done we use the formula as,

W = F.ds

where, F is the force acted on the body and the 'ds' is the displacement vector or the factor,

thus we calculate 'ds' as

AB vector = r2 - r1

AB = (2i + 2j +3k ) - ( i+3j+k)

so we get as,

AB = i -j +2k

now substituting in the formula we get as

W = (i + 2j + 3k ) .(i - j +2k)

W = 1 -2 +6

W = 5 joules

Work done = 5 J

Answer 2

Explanation:

hope this HELPS......