Question

The work done by a force (i+2j+3k N, to displace a body from a point A whose
position vector is (î+3j+k m, to a point B with position vector (2î+2j +3k m is​

Answer 1

Answer:

5 joules

Explanation:

Net displacement = (2-1)î+ (2-3)j+ (3-1)k= i-j+2k

so

work done by a force= net displacement*force= (i-j+2k)*(i+2j+3k)= 1-2+6=5joules