The work done by a force (i+2j+3k) N, to displace a body from a point A whose position is (i+3j+k)m, to a point B with position vector (2ỉ +2j+3k)m is I a) 5 J b) 3J c) 2J d) 10 J
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Answered by
1
Answer:
your question was these (a) 5j (b) 3j (c) 2j (d) 10j
and the right answer is (a) 5j
Answered by
59
Answer:
a) 5 J
Explanation:
★ According to the question,
- Force vector → (i + 2j + 3k) N
- Point A → (i + 3j + k)
- Point B → (2i + 2j + 3k)
We know that:
Displacement = Point B - Point A
⇒ Displacement = (2i + 2j + 3k) - (i + 3j + k)
⇒ Displacement = 2i + 2j + 3k - i - 3j - k
⇒ Displacement = i - j + 2k
Now,
Work = (Force) . (Displacement)
⇒ Work = (i + 2j + 3k) . (i - j + 2k)
⇒ Work = {1(1)} + {2(-1)} + {3(2)}
⇒ Work = 1 + (-2) + 6
⇒ Work = 1 - 2 + 6
⇒ Work = 5 J
∴ Work done = 5 J
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