the work done by a force of 2kgf in displacing a body of 5kg through a displacement 2m is g =10 ms-2ms-2
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Work is merely force times distance, so in this case the force is F = ma = 5 x 9.81 = 49N. The work done then becomes 49Nm x 10m = 490 Joules. If 5 kg is lifted from ground to 10 m, the work done is calculated by multiplying the force (m x g) times the distance (10 m). 5 x 9.8 x 10 meter-newtons.
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